226k views
17 votes
An airplane flies into the wind for 5 hours, traveling 900 miles. The airplane then

turns around and flies with the wind, returning to its starting place in 4 hours.
This can be modeled by the following system of equations, where (s) is the speed
of the plane with no wind and (w) is the speed of the wind.
5(s-w)=900
4(s+w) = 900
What is the speed of the wind in miles per hour?

User Julez
by
8.8k points

1 Answer

2 votes

Answer:

22.5 miles per hour

Explanation:

Given system of equations

5(s-w)=900

4(s+w)=900

Set equations equal to each other

5(s-w)=4(s+w)

5s-5w=4s+4w

s-5w=4w

s=9w

Solve for w using the substitution s=9w

4(s+w)=900

4(9w+w)=900

4(10w)=900

40w=900

w=22.5

Therefore, the speed of the wind is 22.5 miles per hour

User Nick Papagiorgio
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.