Question

In AIJK, the measure of ZK=90°, KJ = 11, IK = 60, and JI = 61. What is the value ofthe cosine of ZJ to the nearest hundredth?

Answer 1

Given the triangle IJK:

`\begin{gathered} m\angle K=90\degree \\ KJ=11,IK=60,JI=61 \end{gathered}`

we will find the cosine of the angle J

so,

`\cos J=(adjacent)/(hypotenuse)`

the adjacent side to the angle J = KJ = 11

the hypotenuse = JI = 61

so,

`\cos J=(11)/(61)=0.18033`

Rounding to the nearest hundredth

So, the answer will be:

`\cos J=0.18`