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UnansweredCorrect AnswerQuestion 6For which of the following gases should the van der Waalscorrection for molecular volume be largest?COBF3HeH₂O0/1 ptsCO2

User Lashon
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Step-by-step explanation:

The Van der Waals equation improves the ideal gas law by adding two different terms. The first one considers the molecular attraction and the second one considers the volume of the gas molecules.

The correction to the volume n*b depends on the size or volume of a molecule, and we can consider that the molecule will have a greater volume as the molar mass increases. So to solve our problem we have to look for the molar mass of each molecule.

molar mass of CO = 28 g/mol

molar mass of BF₃ = 68 g/mol

molar mass of He = 4 g/mol

molar mass of H₂O = 18 g/mol

molar mass of CO₂ = 44 g/mol

BF₃ has the largest molar mass so it is supposed to have the largest correction for the molecular volume.

Answer: BF₃

UnansweredCorrect AnswerQuestion 6For which of the following gases should the van-example-1
User Basil Kosovan
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