By definition:

It is a Function Compositon. It means that you must substitute the function g(x) into the function f(x).
For this case:
![\begin{gathered} f(x)=2+\sqrt[]{x} \\ g(x)=\sqrt[]{x+24} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9wh1mwsgh5dmoymlmzt2nseklper1wgik6.png)
Substitute the function g(x) into the function f(x):
![(f\circ g)(x)=2+\sqrt[]{\sqrt[]{x+24}}](https://img.qammunity.org/2023/formulas/mathematics/college/9rh5088lzrhwfbtt4flo3tqlv60qvxk81u.png)
Simplify:
![(f\circ g)(x)=2+\sqrt[4]{x+24}](https://img.qammunity.org/2023/formulas/mathematics/college/5cm2omqj66chjrdlux4xf7qyin5pv1r4xu.png)
Now, substitute this value into the Composite function and evaluate:

You get:
![\begin{gathered} (f\circ g)(1)=2+\sqrt[4]{1+24} \\ (f\circ g)(1)=2+\sqrt[4]{25} \\ (f\circ g)(1)=2+\sqrt[4]{5^2} \\ (f\circ g)(1)=2+\sqrt[]{5} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/khgdziewo0ix5mgbcnb6mg7hcfje6hjfwl.png)