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what is the friction force on a box that has a mass of 15 kg as it slides across the floor the coefficient of friction of the not very clean floor is 0.25

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*The mass of the object is m=15 kg.

*The coefficient of friction is


\mu=0.25

The frictional force is,f


\begin{gathered} f=\mu mg \\ =0.25*15\text{ kg }*9.8m/s^2 \\ =13.5\text{ N} \end{gathered}

Hence the frictional is 13.5 N.

User Robbie Rosati
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