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Harshil Sharma · Answer 1 · 2023-10-01T22:46:19+0000

Answer

The zeros of f(x) are 2 and 6

Explanation

The function:

has the form:

with the constants: a = 3, b = -24, and c = 36.

We can find the zeros of f(x) with the help of the quadratic formula, as follows:

$\begin{gathered} x_(1,2)=(-b\pm√(b^2-4ac))/(2a) \\ x_(1,2)=\frac{24\pm\sqrt{(-24)^2-4\cdot3\operatorname{\cdot}36}}{2\cdot3} \\ x_(1,2)=(24\pm√(144))/(6) \\ x_1=(24+12)/(6)=6 \\ x_2=(24-12)/(6)=2 \end{gathered}$

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