Question

I need help with this question (with the questions under the equation)

Answer 1

Option C

`(x-2)^2+(y-2)^2=8_{}`
`\begin{gathered} r^2=(0-2)^2+(4-2)^2 \\ r^2=(-2)^2+(-2)^2 \\ r^2=4+4\text{ = 8} \end{gathered}`
`\begin{gathered} \text{Equation of a circle = (x-a)}^2+(y-b)^2=r^2 \\ a=\text{ }(0+4)/(2)=(4)/(2)=2 \\ b=(4+0)/(2)=(4)/(2)=2 \end{gathered}`
`\text{Equation of a circle = (x-2)}^2+^2(y-2)^2=8`