Question

How do i solve 5 and if so could i also get help with number 6

Answer 1

Part 1: 11

Part 2: 19

Part 3: 6859

Explanation:

We have the following function:

`E\mleft(x\mright)=√(4x+33)`

We evaluate when x = 22 and when x = 82, like this:

`\begin{gathered} E\mleft(22\mright)=\sqrt[]{4\cdot22+33}=\sqrt[]{88+33}=\sqrt[]{121} \\ E(22)=11 \\ \\ E(82)=\sqrt[]{4\cdot82+33}=\sqrt[]{328+33}=\sqrt[]{361} \\ E(82)=19 \end{gathered}`

Finally, we determine the value of part 3, like this

`\begin{gathered} E(82)^(E(22)-8) \\ \text{ Replacing:} \\ 19^(11-8)=19^3=6859 \end{gathered}`