ANSWER
The final temperature of the gas is 380K
Step-by-step explanation
Given that;
The initial pressure of the gas is 258kPa
The initial temperature of the gas is 3 degrees Celcius
The final pressure of the gas is 355kPa
To find the final pressure of the gas, follow the steps below
In the given data, the volume of the container is fixed. Hence, the process is called isochoric.
Step 1: Write the gas law at constant volume
![\text{ }(P1)/(T1)=(P2)/(T2)](https://img.qammunity.org/2023/formulas/chemistry/college/ijk9f7479ooyy3iqiwrk2kl7f2k77urhry.png)
Step 2: Convert the temperature to kelvin
![\begin{gathered} t1\text{ }=\text{ 3}\degree C \\ T\text{ }=\text{ t }+\text{ 273.15} \\ \text{ T }=\text{ 3}+273.15 \\ \text{ T }=276.15K \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/paw490l00q3cmpasga90ay83fb0lwp1c3r.png)
Step 3: Substitute the given data into the formula in step 1
![\begin{gathered} (258)/(276.15)=(355)/(T2) \\ \text{ cross multiply} \\ \text{ 258}* T2\text{ }=\text{ 355}*\text{ 276.15} \\ \text{ 258}* T2=\text{ 98033.25} \\ \text{ Divide both sides by 258} \\ \text{ T2 }=\text{ }(98033.25)/(258) \\ \text{ T2 }=\text{ 379.97K} \\ T2\approx380K \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/ij10dmtotsppbimrqleh0n2endifec5y3f.png)
Hence, the final temperature of the gas is 380K