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The perimeter of a rectangle is 58 in with a length of 20 in.What is the area of the rectangle

User Khawar
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1 Answer

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Let say that the rectangle has sides of length a and b. So the perimeter can be written as follows:

perimeter = a + a + b + b

perimeter = 2a + 2b

or

perimeter = 2(a + b)

I choose a to be the longer side, which is 20 in. So a = 20 in . If the perimeter equals 58, we can solve for b:

58 = 2(20 + b)

29 = 20 + b

29 - 20 = b

b = 9 in

Now we can apply the formula to get the area:

area = a x b

area = 20 x 9

area = 180 in²

Answer: area = 180 in²

User Hemanth Poluru
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4.6k points