Question

Write the equation in standard form for the circle passing through (2,3) centered at the origin

Answer 1

Given

coordinates (2, 3) and centre points (0,0)

Find

Equation of a circle

Step-by-step explanation

As we know the standard equation for a circle with centre (h , k ) and r is a radius

`(x-h)^2+(y-k)^2=r^2`

since, center is (0 , 0) , the equation becomes

`x^2+y^2=r^2`

Now, we find the value of radius , it is can find by using the pythagoras theorem,

`r^2=2^2+3^2=4+9=13`

so,

`x^2+y^2=13`

Final Answer

The equation for a circle passing through (2, 3) is

`x^2+y^2=13`