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5) Which value of x satisfies the equation: sin (3x + 5)° = cos (4x + 1)º? A) 12 B):30 C)4 D) 24

User Joe Castro
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1 Answer

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Starting with the equation:


\sin (3x+5)=\cos (4x+1)

Remember the following property:


\cos (90-A)=\sin (A)

Then:


\sin (89-4x)=\sin (90-4x-1)=\cos (4x+1)

Then, the given equation translates to:


\sin (3x+5)=\sin (89-4x)

Then:


3x+5=89-4x

Solve for x:


\begin{gathered} \Rightarrow3x+4x=89-5 \\ \Rightarrow7x=84 \\ \Rightarrow x=(84)/(7) \\ \Rightarrow x=12 \end{gathered}

Therefore, the value of x that satisfies the equation, is:


x=12

User Machycek
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