Question

Solve for 4x^2+8x+3=0

Answer 1

Given the following equation:

`4x^2+8x+3=0`

We will factor the equation to solve for x:

`\begin{gathered} (2x+3)(2x+1)=0 \\ \end{gathered}`

So, there are two values for x that can be calculated as follows:

`\begin{gathered} 2x+3=0\to2x=-3\to x=(-3)/(2) \\ \\ 2x+1=0\to2x=-1\to x=(-1)/(2) \end{gathered}`

So, the answer will be:

`x=\lbrace(-3)/(2),(-1)/(2)\rbrace`