Question

5. Ammonia (NH₂) occupies a volume of 4.5 L at a pressure of 735 mmHg. What volume will it occupy at StandardPressure (1 atm).

Answer 1

`4.35\text{ L}`

Step-by-step explanation:

Here, we want to get the volume occupied at the new temperature

According to Boyle's law, volume and pressure are inversely proportional

Thus, mathematically:

`P_1V_1\text{ = P}_2V_2`

P1 is the initial pressure which is 735 mmHg

V1 is the initial volume which is 4.5 L

P2 is the final pressure which is 1 atm( 760 mmHg)

V2 is the final volume that we want to calculate

Substituting the values, we have it that:

`\begin{gathered} 735\text{ }*\text{ 4.5 = 756 }*\text{ V}_2 \\ \\ V_2\text{ = }\frac{735\text{ }*4.5}{760\text{ }}\text{ = 4.35 L} \end{gathered}`