Question

What magnitude charge creates a 15.43 N/C electric field at a point 2.53 m away?

Answer 1

Given:

The electric field is E = 15.43 N/C

The distance is r = 2.53 m away.

Required: Magnitude of charge.

Step-by-step explanation:

The magnitude of charge can be calculated by the formula

`\begin{gathered} E=(kQ)/(r^2) \\ Q=(Er^2)/(k) \end{gathered}`

Here, Coulomb's constant is

`k\text{ =9}*10^9\text{ N m}^2\text{ / C}^2`

On substituting the values, the magnitude of charge will be

`\begin{gathered} Q=(15.43*(2.53)^2)/(9*10^9) \\ =1.097*10^(-8)\text{ C} \end{gathered}`

Final Answer: The magnitude of the charge is 1.097 x10^(-8) C