1 Answer

Rottitime · Answer 1 · 2023-01-21T09:19:45+0000

Given:

The electric field is E = 15.43 N/C

The distance is r = 2.53 m away.

Required: Magnitude of charge.

Step-by-step explanation:

The magnitude of charge can be calculated by the formula

$\begin{gathered} E=(kQ)/(r^2) \\ Q=(Er^2)/(k) \end{gathered}$

Here, Coulomb's constant is

$k\text{ =9}*10^9\text{ N m}^2\text{ / C}^2$

On substituting the values, the magnitude of charge will be

$\begin{gathered} Q=(15.43*(2.53)^2)/(9*10^9) \\ =1.097*10^(-8)\text{ C} \end{gathered}$

Final Answer: The magnitude of the charge is 1.097 x10^(-8) C

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