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Can someone please please help me on this algebra problem I’m stuck on answering the question?

Can someone please please help me on this algebra problem I’m stuck on answering the-example-1

1 Answer

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Step-by-step explanation:

Midline: it is a horizontal line where half of the function above it and half of the function is below it.

Amplitude: It means how far the function varies from the midline to the above and below.

Period: the distance between two consecutive maximum points (minimum points).

3) From the graph,


\begin{gathered} \text{Midline}=\frac{Maximum\text{ point+ minimum point}}{2} \\ =(3+(-1))/(2) \\ =(3-1)/(2) \\ =(2)/(2) \\ =1 \end{gathered}

Answer: Midline=1

1) Amplitude


\text{Amplitude =}2

2) Periods


\begin{gathered} \text{Period}=6 \\ \Rightarrow b=(2\pi)/(6) \end{gathered}

4) The trigonometric equation is,


\begin{gathered} y=a\cos (b(x-c))+d \\ a=\text{ amplitude} \\ b=\text{period} \\ c=\text{ phase shift} \\ d=\text{ vertical shift} \\ y=2\cos ((2\pi)/(6)x)+1 \end{gathered}

Answer:


y=2\cos ((2\pi)/(6)x)+1

User Izzekil
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