The point-slope form of the linear equation is
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
m is the slope
(x1, y1) is a point on the line
Since a line passes through the point (-9, 8) and has a slope of -2/3, then
![\begin{gathered} (x_1,y_1)=(-9,8) \\ m=-(2)/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8jtyr7mvuxiqv1xrjjhon6qvxi0duwi7qt.png)
Substitute them in the form above
![\begin{gathered} y-8=-(2)/(3)(x--9) \\ y-8=-(2)/(3)(x+9) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9tha54p9wdg9y3hbzuqorwjvt038u5dnqj.png)
The equation of the line in the point-slope form is
![y-8=-(2)/(3)(x+9)](https://img.qammunity.org/2023/formulas/mathematics/college/gu9segjrxduldawpypq6ddwhlwku0qvvxz.png)