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Point Pis on line segment OQ. Given OQ = 4x + 2, PQ = 4x-10 andOP = 3x – 3, determine the numerical length of OQ.

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Answer:

OQ = 62

Explanations:

Given:

OQ = 4x + 2

PQ = 4x - 10

OP = 3x - 3

Since point P is on the line segment OQ, we can conclude that:

OQ = OP + PQ

4x + 2 = (3x-3) + (4x-10)

4x + 2 = 3x + 4x - 3 - 10

4x + 2 = 7x - 13

7x - 4x = 2 + 13

3x = 15

x = 15/3

x = 5

To determine the numerical length of OQ, substitute x = 5 into OQ = 4x+2

OQ = 4(15) + 2

OQ = 60 + 2

OQ = 62

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