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A person drives for 1.00 h at 10.0 km/h and 2.00 h at 20.0 km/h. What is their average speed, in SI units?

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\begin{gathered} Speed_(average)=16.67(km)/(h) \\ Speed=4.63\text{ }(m)/(s) \end{gathered}

Step-by-step explanation

Average speed is defined as the total distance travelled by the time taken


\begin{gathered} Speed_(average)=\frac{total\text{ distance}}{\text{total time}} \\ \end{gathered}

Step 1

find the total distance


\text{distance =sp}eed\cdot time

hence:

a)distance 1

1.00 h at 10.0 km/h


\begin{gathered} \text{distance 1=10 }\frac{\operatorname{km}\text{ }}{h}\cdot1\text{ hour} \\ \text{distance 1}=10\text{ km} \end{gathered}

b) distance 2

2.00 h at 20.0 km/h.


\begin{gathered} \text{distance =sp}eed\cdot time \\ \text{distance }2=20\frac{\operatorname{km}}{h}\cdot2\text{ hours} \\ \text{distance }2=40\text{ km} \end{gathered}

so, the total distance is


\begin{gathered} \text{total distance = 10 km+40 km} \\ \text{total distance =}50\text{ km} \end{gathered}

Step 2

Now, let

total distance = 50 km

total time= 1 hour+2 hours= 3 hours

replace in the formula


\begin{gathered} Speed_(average)=\frac{total\text{ distance}}{\text{total time}} \\ Speed_(average)=\frac{50\text{ km}}{3\text{ hours}} \\ Speed_(average)=16.67\text{ km per hour} \end{gathered}

Step 3

finally, let the answer is SI units:

the units of speed is meter per second or km per hour, so let's convert it


\begin{gathered} \\ Speed=16.67\frac{\operatorname{km}}{h}(\frac{1\text{ hour}}{3600\text{ sec}})(\frac{1000\text{meters}}{1\text{ km}}) \\ Speed=4.63\text{ meters per second} \\ Speed=4.63\text{ }(m)/(s) \end{gathered}

I hope this helps you

A person drives for 1.00 h at 10.0 km/h and 2.00 h at 20.0 km/h. What is their average-example-1
User Manohar
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