we can write an equation

Where A is the total amount and x the number of students.
here we can replace the number of students to calculate the amount
8a)
x=28

x=29

x=30

8b)
if we want to calculate the number of students we must replace the amount
A=300 and solve x

so 35 students can go
8c)
the price for each one is the one that accompanies the x, if we change it would stay like this
