Question

Determine the hydronium concentration in a solution that is 2.0 x 10-4 M LiOH.a. 1.0 x 10^-4b. 2.0 x 10^-4c. 1.0 x 10^-11d. 5.0 x 10^-11

Answer 1

pH + pOH = 14

pOH = -log[OH]

pH = -log[H+]

Lets first find the pH of the solution.

pH = -log[2.0x10^-4]

pH = 3.699

From pH we can get the concentration.

pH + pOH = 14

pOH = 14 - 3.699

pOH = 10.301

pOH = -log[OH]

[OH] = 10^-10.301

[OH] = 5.0x10^-11

The answer is D