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Write the equation of the parabola that has a vertex at (4,6) and passes through (5,8)

User Adijo
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1 Answer

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A parabola has vertex at (4,6) and passes through the point (5,8).

The general equation of the parabola is:


y=a(x-h)^2+k

Where (h,k)=(4,6) in this case so it follows:


y=a(x-4)^2+6

Also it passes through (5,8) so it follows:


\begin{gathered} 8=a(5-4)^2+6 \\ a=2 \end{gathered}

Hence the equation is:


y=2(x-4)^2+6

User Andrea Di Giorgi
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