Question

The 38th percentile of a normal distribution with mean 40 and variance 9 has an X value equal to

Answer 1

37.32

Step-by-step explanation:

First, we need to use the standard normal table and find the value of z that satisfies the following

P(Z < z) = 0.38

Therefore z = -0.3

Then, the x value is equal to:

x = zs + m

Where m is the mean and s is the standard deviation.

x = (-0.3)(9) + 40

x = -2.7 + 40

x = 37.3

Therefore, the x value is 37.32