Question

3x + y + z = 6
3x - 2y + 2z = 14
3x + 3y - 3z = -6

Answer 1

Let's solve for x.

3x+y+z=6

Step 1: Add -y to both sides.

3x+y+z+−y=6+−y

3x+z=−y+6

Step 2: Add -z to both sides.

3x+z+−z=−y+6+−z

3x=−y−z+6

Step 3: Divide both sides by 3.

3x3

=−y−z+6/3

x=−1/3y+−1/3z+2