A(t) = 107 ( 1.015)^t
The growth rate is 1.015-1 = .015 = 1.5%
B(t) = 88(1.025)^t
The growth rate is 1.025 -1 = .025 = 2.5%
B has a faster growth rate
The constant in front is the initial number of trees, A has 107, B has 88 so A has a greater number of trees initially
107-88 =19 tree
A has 19 more trees than B at the start
30 years
A(30) =107 ( 1.015)^30= 167.24958 = 167 trees
B(30) = 88(1.025)^30=184.58594 = 185 trees
Forest B has more trees after 30 years
Rounding to 2 decimal places
184.59 - 167.25 =17.34 trees