50.4k views
5 votes
I need help with my math

User Mikrasya
by
7.3k points

1 Answer

1 vote

Given

Graph

Procedure


\begin{gathered} 3x+2y=-6 \\ 2y=-6-3x \\ y=(-3x-6)/(2) \\ y=-(3)/(2)x-3 \\ \end{gathered}


\begin{gathered} 3y=2x+15 \\ y=(2x+15)/(3) \\ y=(2)/(3)x+(15)/(3) \\ y=(2)/(3)x+5 \\ \end{gathered}


\begin{gathered} y-4x=8 \\ y=4x+8 \end{gathered}


\begin{gathered} y-8=-(1)/(2)(x+4) \\ y-8=-(1)/(2)x-(1)/(2)4 \\ y=-(1)/(2)x-2+8 \\ y=-(1)/(2)x+6 \end{gathered}


\begin{gathered} 3x-4y=8 \\ 4y=-8+3x \\ y=(3x-8)/(4) \\ y=(3)/(4)x-(8)/(4) \\ y=(3)/(4)x-2 \end{gathered}


\begin{gathered} 6x-2y=10 \\ 2y=6x-10 \\ y=(6x-10)/(2) \\ y=(6x)/(2)-(10)/(2) \\ y=3x-5 \end{gathered}

User YannPl
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories