1 Answer

Wigging · Answer 1 · 2023-07-10T15:56:14+0000

A game is said to be fair if the probability of winning is equal to the probability of losing.

The sample space S is given by:

$S=\left\lbrace1,2,3,4,5\right\rbrace$

The event, W, that the spinner lands on an odd number is given by:

$W=\left\lbrace1,3,5\right\rbrace$

The event, L, that the spinner does not land on an odd number is given by:

$L=\left\lbrace2,4\right\rbrace$

The probability of an event E is given by:

$P\left(E\right)=(n\left(E\right))/(n\left(S\right))$

Therefore, the probability of W is given by:

$P\left(W\right)=(n\left(W\right))/(n\left(S\right))=(3)/(5)=0.6$

and

the probability of L is given by:

$P\left(L\right)=(n\left(L\right))/(n\left(S\right))=(2)/(5)=0.4$

Therefore,

$P\left(W\right)P\left(L\right)$

The probability of winning is not equal to the probability of losing.

Therefore, the game is not fair.

The correct answer is choice A

.

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