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The oxidation number of " Z" in sodiumchromite, H₂ZO4, is

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Answer:


Z\text{ = +6}

Step-by-step explanation:

Here, we want to get the value of the oxidation number of Z

Generally, hydrogen has an oxidation number of +1, while oxygen has an oxidation number of -2

The total oxidation number is zero

Thus:


\begin{gathered} 2(+1)\text{ + Z + 4\lparen-2\rparen = 0} \\ 2+Z-8\text{ = 0} \\ Z-6\text{ = 0} \\ Z\text{ = +6} \end{gathered}

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