ANSWER
343.5 m
Step-by-step explanation
Given:
• The time it takes the echo to return, t = 2s
,
• The temperature of the air, T = 21°C
We have to find the distance to the lake.
If we have the speed of sound, s, the distance to the lake, d, is traveled twice by the sound - to the lake and back. Thus, the speed is,
![s=(2d)/(t)](https://img.qammunity.org/2023/formulas/physics/college/9ln0xsytpi50qt9c659s7shc8mi3fge5up.png)
Solving for d,
![d=(s\cdot t)/(2)](https://img.qammunity.org/2023/formulas/physics/college/aw0an8fckyrpol3vdwkf87ocw8kf9qjbu2.png)
We don't know the speed of sound, but we know the temperature of the air. The speed of sound is given by,
![s=331m/s\cdot\sqrt[]{(T)/(273K)}](https://img.qammunity.org/2023/formulas/physics/college/jzjrmsons4xbzk9uv8wbgy11fcv42ou95e.png)
Where T is the temperature in Kelvin. Transform the given temperature from degrees Celsius to Kelvin,
![T=21+273=294K](https://img.qammunity.org/2023/formulas/physics/college/1bq5fzguq16y2qvohfb20eqscdjlrkkj5u.png)
The speed of sound at this temperature is,
![s=331m/s\cdot\sqrt[]{(294K)/(273K)}\approx343.5m/s](https://img.qammunity.org/2023/formulas/physics/college/aq5i3pz17dx2iokdz0e6z4vhpfwjsmjms6.png)
And the distance to the lake is then,
![d=(343.5m/s\cdot2s)/(2)=343.5m](https://img.qammunity.org/2023/formulas/physics/college/jut6o0bsws5de90dn3ggtxs8g4w9k3tvtg.png)
Hence, the distance to the lake is 343.5 m.