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If you stand on top of a hill overlooking a lake and shout, how long is the lake if an echo is heard 2.0 s later on a day when the air temperature is 21°C?

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ANSWER

343.5 m

Step-by-step explanation

Given:

• The time it takes the echo to return, t = 2s

,

• The temperature of the air, T = 21°C

We have to find the distance to the lake.

If we have the speed of sound, s, the distance to the lake, d, is traveled twice by the sound - to the lake and back. Thus, the speed is,


s=(2d)/(t)

Solving for d,


d=(s\cdot t)/(2)

We don't know the speed of sound, but we know the temperature of the air. The speed of sound is given by,


s=331m/s\cdot\sqrt[]{(T)/(273K)}

Where T is the temperature in Kelvin. Transform the given temperature from degrees Celsius to Kelvin,


T=21+273=294K

The speed of sound at this temperature is,


s=331m/s\cdot\sqrt[]{(294K)/(273K)}\approx343.5m/s

And the distance to the lake is then,


d=(343.5m/s\cdot2s)/(2)=343.5m

Hence, the distance to the lake is 343.5 m.

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