Question

Find the 26th term of an arithmetic sequence with \large a_1=-33 and \large d=4. a-130 b71 c-129 d67

Answer 1

Tn = a + ( n- 1 ) d

T 26 = -33 + ( 26 - 1 ) 4

T 26 = -33 + ( 25 x 4 )

= -33 + 100

= 67.............. Option D