the difference in median is 4/3 times the IQR
Step-by-step explanation:
The median for team A = 4
The median for Team B = 8
The difference in median = median for Team B - median for Team A
The difference in median = 8 - 4
The difference in median = 4
The interquartile range (IQR) for team A = upper quartile - lower quartile
The interquartile range (IQR) for team A = Q3 - Q1 = 5 - 2
The interquartile range (IQR) for team A = 3
The interquartile range (IQR) for team B = upper quartile - lower quartile
The interquartile range (IQR) for team B = Q3 - Q1 = 9 - 6
The interquartile range (IQR) for team B = 3
Comparing the difference in median and the interquartile range:
difference in median: the interquartile range = 4:3
![\begin{gathered} \frac{difference\text{ in median}}{In\text{terquartle range}}=(4)/(3) \\ difference\text{ in median = }(4)/(3)* In\text{terquartle range} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/x27l07arpndimvh9w79menq7ns079leu8s.png)
The differnce in median = 4/3 × IQR = 4/3 × 3 = 4
Hence, the difference in median is 4/3 times the IQR