We will have the following:
First, we will calculate the consumption in the timelapse given:
![P=(2.0A)(120V)\Rightarrow P=240.0W](https://img.qammunity.org/2023/formulas/physics/college/xndixwuxntarioiob4bjl816wmkic6dzq5.png)
Now we determine the fraction of one hour that 10 minutes represent:
![x=(10\min\cdot1h)/(60\min)\Rightarrow x=(1)/(6)h](https://img.qammunity.org/2023/formulas/physics/college/p30wvx1aulf99y2ic0daybhh6fyizp7wbf.png)
Then:
![(240.0W)/((1/6h))=1440\cdot(W)/(h)\cdot(kW)/(1000W)=1.44kW/h](https://img.qammunity.org/2023/formulas/physics/college/wloc2920ck5fgnmesxt0vtamdthtrxt1p9.png)
So:
![24\cdot1.44kW/h=34.56\text{kWh}](https://img.qammunity.org/2023/formulas/physics/college/d3upqrdftjohsim95wkfq4fenmqod3sbdk.png)
Then we will have that it will consume 34.56 Kwh each day, the cost of consumption will be given by:
![\text{Cost of consumption=34.56kW/h }\cdot\text{ Cost of each Kw/h}](https://img.qammunity.org/2023/formulas/physics/college/qo1kjcrwig332kot9409uh3iz6qqwmgza9.png)