Step-by-step explanation:

First we have to divide both sides by 7:

And now we have to take square root on both sides:
![\begin{gathered} \sqrt[]{x^2}=\pm\sqrt[]{-3} \\ x=\pm\sqrt[]{-3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1tnr15n8l8wj1xxcidpw12ibqjqsr3ilkk.png)
Since the number inside the square root is negative we can rewrite it as:
![x=\pm\sqrt[]{i^23}=\pm i\sqrt[]{3}](https://img.qammunity.org/2023/formulas/mathematics/college/fwzqsefedh2btp0zj0r1712s5axm5husj5.png)
This is a quadratic equation, so it has two solutions.
Answer:
The solutions are:
• i√3
,
• -i√3