Question

the accompanying table pertains to schedule commercial carriers for a certain country. a) find the mean number of fatalities (round to the nearest tenth as needed) b) find the median (round to the nearest decimal )c) find the mode if there's any

Answer 1

(a)74.9

(b)18

(c)2

Step-by-step explanation:

The number of fatalities from Year 1 to Year 10 are listed below:

14,86,532,2,22,12,22,55,2,2

(a)Mean

`\begin{gathered} \text{Mean}=(14+86+532+2+22+12+22+55+2+2)/(10) \\ =(749)/(10) \\ =74.9 \end{gathered}`

The mean number of fatalities is 74.9

(b)Median

To find the median, the first step is to arrange the data in ascending order.

Ascending Order: 2,2,2,12,14,22,22,55,86,532

The median is the number in the middle.

As can be seen, the data has two numbers in the middle (14 and 22).

So we find the average.

`\begin{gathered} \text{Median}=(14+22)/(2) \\ =(36)/(2) \\ =18 \end{gathered}`

(c)Mode

The mode is the number that appears the most.

We observe that 2 appears three times (which is the highest).

Therefore:

Mode=2