Question

Enter an equation in standard form for the line.Slope is 3, and (-9,0) is on the line.

Answer 1

An equation in standard form must be is in this,

`\text{ Ax + By = }c`

But first, let's make an equation in the slope-intercept form before transforming it into the standard one. We get,

`\text{ y = mx + b}`

Given:

m = 3

(x, y) = (-9,0)

Let's solve for the y-intercept (b) substituting the given in the formula.

`\text{ y = mx + b }\rightarrow\text{ 0 = (3)(-9) + b }\rightarrow\text{ 0 = -27 + b}`
`\text{ b = 27}`

The equation, in Slope-Intercept Form, will be,

`\text{ y = 3x + 27}`

Arranging it into a Standard Form, we get,

`\text{ y = }3x\text{ + 27 }\rightarrow\text{ 3x - y = -27}`

Therefore, the equation of the line in standard form is 3x - y = -27.