The general form of a linear equation is the slope-intercept form:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where m is the slope and b the intercept with the y-axis.
In the question we are asked to graph the line:
![y=(1)/(4)x-1](https://img.qammunity.org/2023/formulas/mathematics/college/5xcejra6sjlscl6xtnbc18ccyvh0sxpcqm.png)
We can identify that the slope is positive,
![m=(1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/84zsmas5pzf0cmuu8tnp0152ye4g2etcq9.png)
And the intercept with the y-axis is,
![b=-1](https://img.qammunity.org/2023/formulas/mathematics/high-school/z6buomokt3q7haydsy0pm8h8ze6l121f2y.png)
Now we can graph the line, to graph the line you can first locate the intercept in the y-axis that is -1, after this, we use the slope. It is important for you to know that the slope is the change in y/ change in x, the slope we have is 1/4.
We locate in the -1 (y-intercept) and count 1 up (because the change in y is positive) and count 4 units to the right (because the change in x is positive), there we locate our other point (4,0), and with those two points located (0,-1) and (4,0) we draw the line.