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1. Line m passes through points (1, 2) and (-3, -4). What is the equation ofthe line parallel to line m that passes through point (0,5)?Ax + 5x + 5D.B.

User Cicero
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1 Answer

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Step 1

Given; Line m passes through points (1, 2) and (-3, -4). What is the equation of the line parallel to line m that passes through point (0,5)?

Step 2

We will find the slope of line m


\begin{gathered} slope=(y_2-y_1)/(x_2-x_1) \\ slope=(-4-2)/(-3-1)=-(6)/(-4)=(3)/(2) \end{gathered}

Step 3

What is the equation of the line parallel to line m that passes through point (0,5)?

Parallel lines have the same slope. Thus


m_1=m_2=(3)/(2)

The equation of a line in slope-intercept form is;


\begin{gathered} y=mx+b \\ y=(3)/(2)x+b \\ b=y-intercept \\ y=5,x=0 \end{gathered}

Thus, the y-intercept of the required line will be;


\begin{gathered} 5=(3)/(2)(0)+b \\ b=5 \end{gathered}

The answer will be;


\begin{gathered} y=1.5x+5 \\ or \\ y=(3)/(2)x+5 \end{gathered}

User The Heist
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