The air pressure at sea level is about 0.1 MPa or 101000 Pa.
The pressure is given as,

Rearranging the above equation in order to get an expression for force,

For the cossestion area of 1 square centimeter, the force is given as,

The force is give as,

Here, g is the acceleration due to gravity .
Rearranging the above equation in order to get mass,

Substituting all known values,

Therefore, the appropriate mass of 1 square centimeter column of air that extends from sea level to the top of atmosphere is 1 kg. Hence, option (b), is the correct choice.