Question

I have the bases and heights down I just don’t know how to solve it …

Answer 1

• Given the base and the height of the parallelogram:

`\begin{gathered} b_p=9mm \\ h_p=6mm \end{gathered}`

You need to multiply them in order to find its area:

`A_p=b_p\cdot h_p=(9mm)(6mm)=54mm^2`

• The formula for calculating the area of a triangle is:

`A_t=(BH)/(2)`

Where "B" is the base of the triangle and "H" is the height.

In this case:

`\begin{gathered} B=3mm \\ H=12mm \end{gathered}`

Then, you get:

`A_t=((3mm)(12mm))/(2)=(36mm^2)/(2)=18mm^2`

• In order to find how many times greater the area of the parallelogram than the area of the triangle is, you need to divide the area of the parallelogram by the area of the triangle:

`(54mm^2)/(18mm^2)=3`

Hence, the answer is: Last option.