To solve this problem, we will use the formula for compound interest:

Where:
• P_N = principal amount after N years,
,
• P_0 = initial principal amount,
,
• r = interest ratio in decimals,
,
• k = compound periods per year.
In this problem, we have:
• N = 9 years,
,
• P_N = ?,
,
• P_0 = $863,
,
• r = 6.2% = 6.2/100 = 0.062,
,
• k = 12 (the inerest is compounded monthly).
Replacing these data in the formula above, we get:

Answer
The balance after 9 years will be $1505.65 to the nearest cent.