Question

Hi it’s a pleasure of you helping may you please do number 5

Answer 1

Let us find each area of the flag using the next formula:

`A=(base\ast height)/(2)`

For the flag on the left:

`\begin{gathered} A=(18in\ast12in)/(2) \\ A=(216in^2)/(2) \\ A=108in^2 \end{gathered}`

For the flag on the right:

`\begin{gathered} A=(36in\ast18in)/(2) \\ A=(648in^2)/(2) \\ A=324in^2 \end{gathered}`

Then, 108 in²*3 = 324in²

Hence, the area of the flag on the right is greater 3 times than the area of the flag on the left.