Question

write an equation in slope intercept form form for the line that passes through (-3,5) and is parallel to the graph of the line y=1/3x+4

Answer 1

If the line is parallel to

`y=(1)/(3)x+4`

Then it has a slope of 1/3.

Using this slope, point (-3, 5) and the slope-point form,

`\begin{gathered} y-5=(1)/(3)(x+3) \\ \rightarrow y-5=(1)/(3)x+1 \end{gathered}`

Clearing y to get the slope-intercept form,

`\begin{gathered} y-5=(1)/(3)x+1 \\ \rightarrow y=(1)/(3)x+6 \end{gathered}`

We get that the equation of the line in slope-intercept form is:

`y=(1)/(3)x+6`