To solve the problem you need to use the following formulas to determine the pH and the pOH.
1) pH=−log[H3O+]
2) pOH=−log[OH−]
3) 14.00=pH+pOH
Given that the pOH is 6.840 the pH will be
pH=14.00-6.840=7.160
To determine the concentrations we need to solve equations 1) and 2). This gives us
![[H_3O^+]=10^(-pH)](https://img.qammunity.org/2023/formulas/chemistry/college/y9s75cov802yt5uieoowczrk3w2ourzssx.png)
![[OH^-]=10^(-pOH)](https://img.qammunity.org/2023/formulas/chemistry/college/805pftnpdm7eep0n1fca1vl0yuguyqxod7.png)
Solving using the pH and pOH values
![[H_3O^+]=10^(-7.16)=6.9183*10^(-8)\text{ M}](https://img.qammunity.org/2023/formulas/chemistry/college/l2fm5c851tgm8vz9emptbqsha18vu7or98.png)
![[OH^-]=10^(-6.84)=1.4454\text{ }*10^(-7)\text{ M}](https://img.qammunity.org/2023/formulas/chemistry/college/tm67ajrxqy8gzp16b5xey2dug1gfycy4xk.png)