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Identify the horizontal asymptote of the function below *y= 2* + 1O y=0O y=1O y=2O None of the above

User Maze
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1 Answer

2 votes

y=2^x+1

Let's find the limit:


\begin{gathered} \lim _(x\to-\infty)(2^x+1)=\lim _(x\to-\infty)2^x+\lim _(x\to-\infty)1 \\ where\colon \\ \lim _(x\to-\infty)2^x=2^{\lim _(x\to-\infty)x}=0 \\ so\colon \\ \lim _(x\to-\infty)(2^x+1)=1 \end{gathered}

Therefore, the horizontal asymptote is:


y=1

User Deadfish
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