We are given the function:
![f(x)=√(x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/873fcmlq7rb1chu99quxya8598mspyza85.png)
we are asked to do the following transformations:
Part A.
![g(x)=f(x+4)](https://img.qammunity.org/2023/formulas/mathematics/college/od36knt9ieg0519ijmdb597voejhxqliax.png)
This is s transformation of the form:
![h(x)=f(x-a)](https://img.qammunity.org/2023/formulas/mathematics/college/jz9e7q9e8n98cai7kv996fbi0vvsewybr8.png)
In this case, "a" is a negative number. This is a translation of the graph 4 units to the left since "a" is negative. If "a" were positive then it would be a translation to the right.
To determine the function we substitute the value of "x" in f(x) for "x + 4", like this:
![g(x)=√(x+4)](https://img.qammunity.org/2023/formulas/mathematics/high-school/4mu07esv3s9ti1l6h237740rrza6m1ua8l.png)
The graph of the function is:
Part B.
We are given the follwing transformation:
![g(x)=2f(2x-1)](https://img.qammunity.org/2023/formulas/mathematics/college/7yey7igcggvgeutmkiuwzfbufzjfz2e7om.png)
The first transformation is to stretch the function by a factor of "2", which means that we change "x" for "2x" in f(x):
![f(2x)=√(2x)](https://img.qammunity.org/2023/formulas/mathematics/college/20uvqpedrih7nfuzav7a5z5ttyow9586cg.png)
Now, we translate the streched function 0.5 units to the right. That means that we change "2x" for "2x - 1";
![f(2x-1)=√(2x-1)](https://img.qammunity.org/2023/formulas/mathematics/college/cm09lp6c93bfkc2lhxkmze1wjm1bh1m4j3.png)
Now, we multiply the function by 2. This means that the function is stretched by a factor of 2.
![g(x)=2f(2x-1)=2√(2x-1)](https://img.qammunity.org/2023/formulas/mathematics/college/p7lwris3tl1k626hwvrib2sd20q544lsex.png)
The graph of the function is the following:
Part c. In this case, this is the function translated by 1 unit to the right. The graph is the following:
Part D. This is the function translated 1 uni