Question

Write an equation of the line that passes through point P and is parallel to the line with thegiven equation. P(42), y = -3x + 3

Answer 1

The general equation of a line is given as y = mx + c wher

m = gradient and

c = intercept on the y axis.

The line has an equation of y = -3x + 3

When two lines are parallel, they have the same gradient so the line that passes through point P has a gradient of -3. The formulae to get the eqn is given below:

`(y-y_1)/(x-x_1)=m`

Substituting, we have:

`-3\text{ = }(y-2)/(x-4)`

Cross multiplying, we have: -3x + 12 = y - 2

Adding 2 to both sides give: -3x +12 + 2 = y

Therefore, equation of the line is y = -3x +14