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Your middle school is having a carnival. Admission to the carnival is $8.25 and each game inside the carnival costs $0.50.Part 1: Write an inequality to represent the possible number of games that can be played with $20.75. Let g representthe number of games you play.Part 2: Solve the inequality.Part 3: Is your answer reasonable? Explain why or why not.

User Hastur
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1 Answer

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ANSWER:

Part 1:


8.25+0.50g\leqslant20.75

Part 2:


\begin{gathered} 8.25+0.50g-8.25\le20.75-8.25 \\ (0.50g)/(0.5)\le(12.5)/(0.5) \\ g\leq25 \end{gathered}

Part 3:

The answer is only reasonable to deduce the maximum number, the interval is not reasonable because it includes negative numbers, which is not possible. The answer is only reasonable if g goes from 0 to 25

Explanation:

Given:

Price per game: $0.5

Admission price: $8.25

If we have a total of $20.75, we establish the following inequality:


8.25+0.50g\le20.75

We solve for g:


\begin{gathered} 8.25+0.50g-8.25\le20.75-8.25 \\ (0.50g)/(0.5)\le(12.5)/(0.5) \\ g\leq25 \end{gathered}

We graph this:

In other words, that amount of money is limited to 25 games, so the answer makes sense, but if we see it from the graph, we can see that g can take negative values, which does not make sense.

Therefore, it is only reasonable to know the maximum limit, the answer as an interval does not make sense.

Your middle school is having a carnival. Admission to the carnival is $8.25 and each-example-1
User Zuleyka
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