28.2k views
0 votes
Triangle ABC is similar to triangle WXY (A photo will be provided)

User Ecortazar
by
7.9k points

1 Answer

7 votes

Let x be the length of WX


(16)/(28)=(x)/(24)\rightarrow x=24\cdot(16)/(28)=(96)/(7)

let y be the length of YZ. We get


(16)/(28)=(y)/(14)\rightarrow y=14\cdot(16)/(28)=8

let z be the length of AD


(28)/(16)=(z)/(12)\rightarrow z=12\cdot(28)/(16)=21

let c be the length of DB and d the length of ZX we get


(21)/(12)=(c)/(d)\rightarrow d\cdot(7)/(4)=c

User Daniel Centore
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories