ANSWER
R'(-3,6)
T'(-3, 3)
D' (-5, 3)
C' (-5, 7)
Explanation:
Given information
In the figure given, the image in the graph consists of 4 vertices which are listed below as;
R(1,1)
T(1, -2)
D(-1, -2)
C(-1, 2)
According to the question, we were told that the image is translated into 4 units to the left and 5 units to the up to create another quadrilateral R' T' D' C'
To translate a function to the left, means a negative value will translate it to the left
Hence, 4 units to the left will be (x - 4)
To translate a function to the up means a positive value to the y-axis
Hence, 5 units to the up will be (y + 5)
Therefore, the general rule for the translation is
(x, y) -----------------------> (x - 4, y + 5)
Since the original coordinates are;
R(1,1)
T(1, -2)
D(-1, -2)
C(-1, 2)
Using the general rule above
R(1,1) ----------------> R'(1 - 4, 1 + 5)
-----------------> R'(-3, 6)
Therefore, R(1,1) is translated to R'(-3, 6)
T(1, -2) ---------------> T'(1- 4, -2 + 5)
----------------> T'(-3, 3)
Therefore, T(1, -2) is translated to T'(-3, 3)
D(-1, -2) ----------------> D'(-1 - 4, -2 + 5)
----------------> D' (-5, 3)
Therefore, D(-1, -2) is translated to (-5, 3)
C(-1,2) ----------------> C'(-1 - 4, 2 + 5)
C(-1, 2) ---------------> C'(-5, 7)
Therefore, C(-1, 2) is translated to C'(-5, 7)
R'(-3,6)
T'(-3, 3)
D' (-5, 3)
C' (-5, 7)