Question

What is the equation for a line that has a slope of -6 and passes through the point (2,-8)

Answer 1

slope m = -6

coordinate (2,-8) = (x,y)

x1 = 2 and y1 = -8

`\begin{gathered} \\ \text{Slope and one point form equation of a line} \\ m\text{ = }(y-y_1)/(x-x_1) \\ -6\text{ = }\frac{y\text{ -(-8)}}{x\text{ - 2}} \\ \\ -6\text{ = }\frac{y\text{ + 8}}{x\text{ - 2}} \\ \text{Cross multiple} \\ y\text{ + 8 = -6(x - 2)} \\ y\text{ + 8 = -6x + 12} \\ y\text{ = -6x + 12 - 8} \\ y\text{ = -6x + 4} \end{gathered}`